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114124001433 = 3132926256447
BaseRepresentation
bin110101001001001010…
…0100001000010011001
3101220120111102221210220
41222102110201002121
53332211221021213
6124232225230253
711150046002151
oct1522224410231
9356514387726
10114124001433
1144444029462
121a14ba92389
13a9b9a16940
145748bb5761
152e7e1b3e23
hex1a92521099

114124001433 has 8 divisors (see below), whose sum is σ = 163870361088. Its totient is φ = 70230154704.

The previous prime is 114124001419. The next prime is 114124001449. The reversal of 114124001433 is 334100421411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114124001433 - 232 = 109829034137 is a prime.

It is not an unprimeable number, because it can be changed into a prime (114124001413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1463128185 + ... + 1463128262.

It is an arithmetic number, because the mean of its divisors is an integer number (20483795136).

Almost surely, 2114124001433 is an apocalyptic number.

114124001433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

114124001433 is a deficient number, since it is larger than the sum of its proper divisors (49746359655).

114124001433 is a wasteful number, since it uses less digits than its factorization.

114124001433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2926256463.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 114124001433 its reverse (334100421411), we get a palindrome (448224422844).

The spelling of 114124001433 in words is "one hundred fourteen billion, one hundred twenty-four million, one thousand, four hundred thirty-three".

Divisors: 1 3 13 39 2926256447 8778769341 38041333811 114124001433