1141241204113 has 4 divisors (see below), whose sum is σ = 1144958602480. Its totient is φ = 1137523805748.

The previous prime is 1141241204111. The next prime is 1141241204149. The reversal of 1141241204113 is 3114021421411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1141241204113 - 2¹ = 1141241204111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141241204111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1858698723 + ... + 1858699336.

It is an arithmetic number, because the mean of its divisors is an integer number (286239650620).

Almost surely, 2^{1141241204113} is an apocalyptic number.

It is an amenable number.

1141241204113 is a deficient number, since it is larger than the sum of its proper divisors (3717398367).

1141241204113 is an equidigital number, since it uses as much as digits as its factorization.

1141241204113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3717398366.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1141241204113 its reverse (3114021421411), we get a palindrome (4255262625524).

The spelling of 1141241204113 in words is "one trillion, one hundred forty-one billion, two hundred forty-one million, two hundred four thousand, one hundred thirteen".