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11412434001 = 329789127703
BaseRepresentation
bin10101010000011101…
…11110110001010001
31002110100111201022210
422220032332301101
5141333040342001
65124240022333
7552545042223
oct125016766121
932410451283
1011412434001
114927026641
1222660019a9
1310cb500637
147a3990413
1546bdabdd6
hex2a83bec51

11412434001 has 8 divisors (see below), whose sum is σ = 15217208640. Its totient is φ = 7607974352.

The previous prime is 11412433943. The next prime is 11412434017. The reversal of 11412434001 is 10043421411.

11412434001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11412434001 - 26 = 11412433937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11412439001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25516 + ... + 153218.

It is an arithmetic number, because the mean of its divisors is an integer number (1902151080).

Almost surely, 211412434001 is an apocalyptic number.

It is an amenable number.

11412434001 is a deficient number, since it is larger than the sum of its proper divisors (3804774639).

11412434001 is a wasteful number, since it uses less digits than its factorization.

11412434001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157495.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 11412434001 its reverse (10043421411), we get a palindrome (21455855412).

The spelling of 11412434001 in words is "eleven billion, four hundred twelve million, four hundred thirty-four thousand, one".

Divisors: 1 3 29789 89367 127703 383109 3804144667 11412434001