Base | Representation |
---|---|
bin | 10101010000011101… |
… | …11110110001100001 |
3 | 1002110100111201100101 |
4 | 22220032332301201 |
5 | 141333040342032 |
6 | 5124240022401 |
7 | 552545042245 |
oct | 125016766141 |
9 | 32410451311 |
10 | 11412434017 |
11 | 4927026656 |
12 | 2266001a01 |
13 | 10cb50064a |
14 | 7a3990425 |
15 | 46bdabde7 |
hex | 2a83bec61 |
11412434017 has 2 divisors, whose sum is σ = 11412434018. Its totient is φ = 11412434016.
The previous prime is 11412433943. The next prime is 11412434057. The reversal of 11412434017 is 71043421411.
11412434017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9569534976 + 1842899041 = 97824^2 + 42929^2 .
It is a cyclic number.
It is not a de Polignac number, because 11412434017 - 27 = 11412433889 is a prime.
It is not a weakly prime, because it can be changed into another prime (11412434057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706217008 + 5706217009.
It is an arithmetic number, because the mean of its divisors is an integer number (5706217009).
Almost surely, 211412434017 is an apocalyptic number.
It is an amenable number.
11412434017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412434017 is an equidigital number, since it uses as much as digits as its factorization.
11412434017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 11412434017 its reverse (71043421411), we get a palindrome (82455855428).
The spelling of 11412434017 in words is "eleven billion, four hundred twelve million, four hundred thirty-four thousand, seventeen".
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