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1141244346055 = 51121886354291
BaseRepresentation
bin10000100110110111011…
…101101011111011000111
311001002202021120122010011
4100212313131223323013
5122144232023033210
62232140323011051
7145311045612262
oct20466735537307
94032667518104
101141244346055
113aaaa9754700
12165220509a87
13838078aaa78
143d345029cd9
151ea46832d8a
hex109b776bec7

1141244346055 has 12 divisors (see below), whose sum is σ = 1505310725016. Its totient is φ = 829995887600.

The previous prime is 1141244346007. The next prime is 1141244346083. The reversal of 1141244346055 is 5506434421411.

It is not a de Polignac number, because 1141244346055 - 29 = 1141244345543 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1141244345999 and 1141244346017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 943176541 + ... + 943177750.

It is an arithmetic number, because the mean of its divisors is an integer number (125442560418).

Almost surely, 21141244346055 is an apocalyptic number.

1141244346055 is a deficient number, since it is larger than the sum of its proper divisors (364066378961).

1141244346055 is a wasteful number, since it uses less digits than its factorization.

1141244346055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1886354318 (or 1886354307 counting only the distinct ones).

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 1141244346055 its reverse (5506434421411), we get a palindrome (6647678767466).

The spelling of 1141244346055 in words is "one trillion, one hundred forty-one billion, two hundred forty-four million, three hundred forty-six thousand, fifty-five".

Divisors: 1 5 11 55 121 605 1886354291 9431771455 20749897201 103749486005 228248869211 1141244346055