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1141254143351 = 7417095608597
BaseRepresentation
bin10000100110111000000…
…011000011110101110111
311001002202222000101110222
4100212320003003311313
5122144242030041401
62232141313004555
7145311225105650
oct20467003036567
94032688011428
101141254143351
11400004236543
1216522385375b
138380992b29a
143d34645a527
151ea4761ac1b
hex109b80c3d77

1141254143351 has 16 divisors (see below), whose sum is σ = 1337987138880. Its totient is φ = 953012632320.

The previous prime is 1141254143297. The next prime is 1141254143399. The reversal of 1141254143351 is 1533414521411.

It is a de Polignac number, because none of the positive numbers 2k-1141254143351 is a prime.

It is a super-2 number, since 2×11412541433512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1141254143551) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2600816 + ... + 3007781.

It is an arithmetic number, because the mean of its divisors is an integer number (83624196180).

Almost surely, 21141254143351 is an apocalyptic number.

1141254143351 is a deficient number, since it is larger than the sum of its proper divisors (196732995529).

1141254143351 is an equidigital number, since it uses as much as digits as its factorization.

1141254143351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5609354.

The product of its digits is 28800, while the sum is 35.

Adding to 1141254143351 its reverse (1533414521411), we get a palindrome (2674668664762).

The spelling of 1141254143351 in words is "one trillion, one hundred forty-one billion, two hundred fifty-four million, one hundred forty-three thousand, three hundred fifty-one".

Divisors: 1 7 41 287 709 4963 29069 203483 5608597 39260179 229952477 1609667339 3976495273 27835466911 163036306193 1141254143351