Base | Representation |
---|---|
bin | 110101001001001101… |
… | …0011100010111000111 |
3 | 101220120121100220002201 |
4 | 1222102122130113013 |
5 | 3332212120231033 |
6 | 124232322415331 |
7 | 11150065133005 |
oct | 1522232342707 |
9 | 356517326081 |
10 | 114125555143 |
11 | 4444499a816 |
12 | 1a150501547 |
13 | a9ba13bbb2 |
14 | 574909ba75 |
15 | 2e7e3be47d |
hex | 1a9269c5c7 |
114125555143 has 4 divisors (see below), whose sum is σ = 114173691448. Its totient is φ = 114077418840.
The previous prime is 114125555123. The next prime is 114125555153. The reversal of 114125555143 is 341555521411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114125555143 is a prime.
It is a super-3 number, since 3×1141255551433 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114125555123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24064596 + ... + 24069337.
It is an arithmetic number, because the mean of its divisors is an integer number (28543422862).
Almost surely, 2114125555143 is an apocalyptic number.
114125555143 is a deficient number, since it is larger than the sum of its proper divisors (48136305).
114125555143 is an equidigital number, since it uses as much as digits as its factorization.
114125555143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48136304.
The product of its digits is 60000, while the sum is 37.
The spelling of 114125555143 in words is "one hundred fourteen billion, one hundred twenty-five million, five hundred fifty-five thousand, one hundred forty-three".
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