11413034333113 has 4 divisors (see below), whose sum is σ = 13043467809280. Its totient is φ = 9782600856948.

The previous prime is 11413034332967. The next prime is 11413034333119. The reversal of 11413034333113 is 31133343031411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11413034333113 - 2²¹ = 11413032235961 is a prime.

It is a super-2 number, since 2×11413034333113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11413034333119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 815216738073 + ... + 815216738086.

It is an arithmetic number, because the mean of its divisors is an integer number (3260866952320).

Almost surely, 2^{11413034333113} is an apocalyptic number.

It is an amenable number.

11413034333113 is a deficient number, since it is larger than the sum of its proper divisors (1630433476167).

11413034333113 is an equidigital number, since it uses as much as digits as its factorization.

11413034333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1630433476166.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 11413034333113 its reverse (31133343031411), we get a palindrome (42546377364524).

The spelling of 11413034333113 in words is "eleven trillion, four hundred thirteen billion, thirty-four million, three hundred thirty-three thousand, one hundred thirteen".