Base | Representation |
---|---|
bin | 1010011000010100111011… |
… | …0011001010111001101011 |
3 | 1111102002002002100222002111 |
4 | 2212011032303022321223 |
5 | 2443442411314023230 |
6 | 40135025521343151 |
7 | 2255365010361433 |
oct | 246051663127153 |
9 | 44362062328074 |
10 | 11413050142315 |
11 | 370027a2a4398 |
12 | 1343b13497ab7 |
13 | 64a32763c1a3 |
14 | 2b65749d72c3 |
15 | 14bd2db0b92a |
hex | a614eccae6b |
11413050142315 has 8 divisors (see below), whose sum is σ = 14291123656608. Its totient is φ = 8733464456640.
The previous prime is 11413050142301. The next prime is 11413050142391. The reversal of 11413050142315 is 51324105031411.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11413050142315 - 215 = 11413050109547 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49621957026 + ... + 49621957255.
It is an arithmetic number, because the mean of its divisors is an integer number (1786390457076).
Almost surely, 211413050142315 is an apocalyptic number.
11413050142315 is a deficient number, since it is larger than the sum of its proper divisors (2878073514293).
11413050142315 is an equidigital number, since it uses as much as digits as its factorization.
11413050142315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99243914309.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 11413050142315 its reverse (51324105031411), we get a palindrome (62737155173726).
The spelling of 11413050142315 in words is "eleven trillion, four hundred thirteen billion, fifty million, one hundred forty-two thousand, three hundred fifteen".
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