114131402017 has 4 divisors (see below), whose sum is σ = 114132160276. Its totient is φ = 114130643760.

The previous prime is 114131401973. The next prime is 114131402027. The reversal of 114131402017 is 710204131411.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 113487460641 + 643941376 = 336879^2 + 25376^2 .

It is a cyclic number.

It is not a de Polignac number, because 114131402017 - 2²³ = 114123013409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114131401982 and 114131402000.

It is not an unprimeable number, because it can be changed into a prime (114131402027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68538 + ... + 482659.

It is an arithmetic number, because the mean of its divisors is an integer number (28533040069).

Almost surely, 2^114131402017 is an apocalyptic number.

It is an amenable number.

114131402017 is a deficient number, since it is larger than the sum of its proper divisors (758259).

114131402017 is an equidigital number, since it uses as much as digits as its factorization.

114131402017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 758258.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 114131402017 its reverse (710204131411), we get a palindrome (824335533428).

The spelling of 114131402017 in words is "one hundred fourteen billion, one hundred thirty-one million, four hundred two thousand, seventeen".