Base | Representation |
---|---|
bin | 10101010000100011… |
… | …11010110010100011 |
3 | 1002110101221211202010 |
4 | 22220101322302203 |
5 | 141333240013011 |
6 | 5124304324003 |
7 | 552554430420 |
oct | 125021726243 |
9 | 32411854663 |
10 | 11413204131 |
11 | 492750220a |
12 | 2266313603 |
13 | 10cb710034 |
14 | 7a3b10d47 |
15 | 46beb01a6 |
hex | 2a847aca3 |
11413204131 has 32 divisors (see below), whose sum is σ = 17480995840. Its totient is φ = 6488366976.
The previous prime is 11413204129. The next prime is 11413204139. The reversal of 11413204131 is 13140231411.
It is not a de Polignac number, because 11413204131 - 21 = 11413204129 is a prime.
It is a super-2 number, since 2×114132041312 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 11413204098 and 11413204107.
It is not an unprimeable number, because it can be changed into a prime (11413204139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5624025 + ... + 5626053.
It is an arithmetic number, because the mean of its divisors is an integer number (546281120).
Almost surely, 211413204131 is an apocalyptic number.
11413204131 is a deficient number, since it is larger than the sum of its proper divisors (6067791709).
11413204131 is a wasteful number, since it uses less digits than its factorization.
11413204131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3283.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 11413204131 its reverse (13140231411), we get a palindrome (24553435542).
The spelling of 11413204131 in words is "eleven billion, four hundred thirteen million, two hundred four thousand, one hundred thirty-one".
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