11413210045 has 4 divisors (see below), whose sum is σ = 13695852060. Its totient is φ = 9130568032.

The previous prime is 11413210037. The next prime is 11413210051. The reversal of 11413210045 is 54001231411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54001231411 = 257 ⋅210121523.

It can be written as a sum of positive squares in 2 ways, for example, as 8439361956 + 2973848089 = 91866^2 + 54533^2 .

It is a cyclic number.

It is not a de Polignac number, because 11413210045 - 2³ = 11413210037 is a prime.

It is a super-2 number, since 2×11413210045² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11413209998 and 11413210025.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1141321000 + ... + 1141321009.

It is an arithmetic number, because the mean of its divisors is an integer number (3423963015).

Almost surely, 2^11413210045 is an apocalyptic number.

It is an amenable number.

11413210045 is a deficient number, since it is larger than the sum of its proper divisors (2282642015).

11413210045 is an equidigital number, since it uses as much as digits as its factorization.

11413210045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2282642014.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 11413210045 its reverse (54001231411), we get a palindrome (65414441456).

The spelling of 11413210045 in words is "eleven billion, four hundred thirteen million, two hundred ten thousand, forty-five".