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114132156451 = 1011130021351
BaseRepresentation
bin110101001001011001…
…1101000000000100011
3101220121001210021101121
41222102303220000203
53332220313001301
6124233120113111
711150205215545
oct1522263500043
9356531707347
10114132156451
1144448699445
121a152765797
13a9bb6107b1
145749cd9695
152e7ec753a1
hex1a92ce8023

114132156451 has 4 divisors (see below), whose sum is σ = 115262177904. Its totient is φ = 113002135000.

The previous prime is 114132156427. The next prime is 114132156461. The reversal of 114132156451 is 154651231411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114132156451 - 213 = 114132148259 is a prime.

It is a super-2 number, since 2×1141321564512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114132156401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565010575 + ... + 565010776.

It is an arithmetic number, because the mean of its divisors is an integer number (28815544476).

Almost surely, 2114132156451 is an apocalyptic number.

114132156451 is a deficient number, since it is larger than the sum of its proper divisors (1130021453).

114132156451 is a wasteful number, since it uses less digits than its factorization.

114132156451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1130021452.

The product of its digits is 14400, while the sum is 34.

Adding to 114132156451 its reverse (154651231411), we get a palindrome (268783387862).

The spelling of 114132156451 in words is "one hundred fourteen billion, one hundred thirty-two million, one hundred fifty-six thousand, four hundred fifty-one".

Divisors: 1 101 1130021351 114132156451