Base | Representation |
---|---|
bin | 1010011000010101100011… |
… | …1111110110110101001111 |
3 | 1111102002112000022122012002 |
4 | 2212011120333312311033 |
5 | 2443443234114141033 |
6 | 40135054512502515 |
7 | 2255402155602062 |
oct | 246053077666517 |
9 | 44362460278162 |
10 | 11413221240143 |
11 | 3700357936758 |
12 | 1343b6084aa3b |
13 | 64a353c170c8 |
14 | 2b658d6148d9 |
15 | 14bd3db573e8 |
hex | a6158ff6d4f |
11413221240143 has 4 divisors (see below), whose sum is σ = 11909448250608. Its totient is φ = 10916994229680.
The previous prime is 11413221240089. The next prime is 11413221240163. The reversal of 11413221240143 is 34104212231411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11413221240143 - 212 = 11413221236047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11413221240163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248113505198 + ... + 248113505243.
It is an arithmetic number, because the mean of its divisors is an integer number (2977362062652).
Almost surely, 211413221240143 is an apocalyptic number.
11413221240143 is a deficient number, since it is larger than the sum of its proper divisors (496227010465).
11413221240143 is an equidigital number, since it uses as much as digits as its factorization.
11413221240143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 496227010464.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 11413221240143 its reverse (34104212231411), we get a palindrome (45517433471554).
The spelling of 11413221240143 in words is "eleven trillion, four hundred thirteen billion, two hundred twenty-one million, two hundred forty thousand, one hundred forty-three".
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