Base | Representation |
---|---|
bin | 110101001001011011… |
… | …1001110101010101111 |
3 | 101220121010120021101110 |
4 | 1222102313032222233 |
5 | 3332221033214411 |
6 | 124233152243103 |
7 | 11150216232162 |
oct | 1522267165257 |
9 | 356533507343 |
10 | 114133101231 |
11 | 44449184256 |
12 | 1a152b40493 |
13 | a9bb881836 |
14 | 574a0a3ad9 |
15 | 2e7edb02a6 |
hex | 1a92dceaaf |
114133101231 has 4 divisors (see below), whose sum is σ = 152177468312. Its totient is φ = 76088734152.
The previous prime is 114133101211. The next prime is 114133101311. The reversal of 114133101231 is 132101331411.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 114133101231 - 215 = 114133068463 is a prime.
It is a super-2 number, since 2×1141331012312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114133101198 and 114133101207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114133101211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19022183536 + ... + 19022183541.
It is an arithmetic number, because the mean of its divisors is an integer number (38044367078).
Almost surely, 2114133101231 is an apocalyptic number.
114133101231 is a deficient number, since it is larger than the sum of its proper divisors (38044367081).
114133101231 is an equidigital number, since it uses as much as digits as its factorization.
114133101231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38044367080.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 114133101231 its reverse (132101331411), we get a palindrome (246234432642).
The spelling of 114133101231 in words is "one hundred fourteen billion, one hundred thirty-three million, one hundred one thousand, two hundred thirty-one".
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