Base | Representation |
---|---|
bin | 10101010000100101… |
… | …10100101001110111 |
3 | 1002110102101212212100 |
4 | 22220102310221313 |
5 | 141333320104033 |
6 | 5124313353143 |
7 | 552556435416 |
oct | 125022645167 |
9 | 32412355770 |
10 | 11413441143 |
11 | 4927654295 |
12 | 22664087b3 |
13 | 10cb793b90 |
14 | 7a3b7347d |
15 | 46c00a513 |
hex | 2a84b4a77 |
11413441143 has 12 divisors (see below), whose sum is σ = 17754241960. Its totient is φ = 7023656016.
The previous prime is 11413441141. The next prime is 11413441159. The reversal of 11413441143 is 34114431411.
11413441143 is a `hidden beast` number, since 114 + 134 + 411 + 4 + 3 = 666.
11413441143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11413441143 - 21 = 11413441141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11413441141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 48775273 + ... + 48775506.
Almost surely, 211413441143 is an apocalyptic number.
11413441143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11413441143 is a deficient number, since it is larger than the sum of its proper divisors (6340800817).
11413441143 is a wasteful number, since it uses less digits than its factorization.
11413441143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97550798 (or 97550795 counting only the distinct ones).
The product of its digits is 2304, while the sum is 27.
Adding to 11413441143 its reverse (34114431411), we get a palindrome (45527872554).
The spelling of 11413441143 in words is "eleven billion, four hundred thirteen million, four hundred forty-one thousand, one hundred forty-three".
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