Base | Representation |
---|---|
bin | 11001111100111101010110… |
… | …110000000111001010100011 |
3 | 112222010200211120121202022021 |
4 | 121330331112300013022203 |
5 | 104430033123101002120 |
6 | 1042431142245322311 |
7 | 33020233561344442 |
oct | 3174752660071243 |
9 | 488120746552267 |
10 | 114140211344035 |
11 | 33406656746898 |
12 | 10975179a06397 |
13 | 4b8c4b6688706 |
14 | 20285b69a4d59 |
15 | d2e0aec39aaa |
hex | 67cf56c072a3 |
114140211344035 has 8 divisors (see below), whose sum is σ = 137349780783840. Its totient is φ = 91057817627904.
The previous prime is 114140211344021. The next prime is 114140211344041. The reversal of 114140211344035 is 530443112041411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114140211344035 - 215 = 114140211311267 is a prime.
It is a super-2 number, since 2×1141402113440352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31793928942 + ... + 31793932531.
It is an arithmetic number, because the mean of its divisors is an integer number (17168722597980).
Almost surely, 2114140211344035 is an apocalyptic number.
114140211344035 is a deficient number, since it is larger than the sum of its proper divisors (23209569439805).
114140211344035 is an equidigital number, since it uses as much as digits as its factorization.
114140211344035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63587861837.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 114140211344035 its reverse (530443112041411), we get a palindrome (644583323385446).
The spelling of 114140211344035 in words is "one hundred fourteen trillion, one hundred forty billion, two hundred eleven million, three hundred forty-four thousand, thirty-five".
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