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11414100103 = 71630585729
BaseRepresentation
bin10101010000101010…
…10101100010000111
31002110110122100210021
422220111111202013
5141334002200403
65124335440011
7552565151530
oct125025254207
932413570707
1011414100103
114927a6438a
122266686007
1310cb964ab3
147a3ca5687
1546c0da8bd
hex2a8555887

11414100103 has 4 divisors (see below), whose sum is σ = 13044685840. Its totient is φ = 9783514368.

The previous prime is 11414100079. The next prime is 11414100107. The reversal of 11414100103 is 30100141411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11414100103 is a prime.

It is a super-2 number, since 2×114141001032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11414100107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 815292858 + ... + 815292871.

It is an arithmetic number, because the mean of its divisors is an integer number (3261171460).

Almost surely, 211414100103 is an apocalyptic number.

11414100103 is a deficient number, since it is larger than the sum of its proper divisors (1630585737).

11414100103 is an equidigital number, since it uses as much as digits as its factorization.

11414100103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1630585736.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11414100103 its reverse (30100141411), we get a palindrome (41514241514).

The spelling of 11414100103 in words is "eleven billion, four hundred fourteen million, one hundred thousand, one hundred three".

Divisors: 1 7 1630585729 11414100103