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1141411311111 = 3419279766757
BaseRepresentation
bin10000100111000001011…
…010100110111000000111
311001010011220202100010010
4100213001122212320013
5122200102243423421
62232205045401303
7145315144031001
oct20470132467007
94033156670103
101141411311111
11400084a23a55
12165268409233
1383833369866
143d35d28d371
151ea56314076
hex109c16a6e07

1141411311111 has 8 divisors (see below), whose sum is σ = 1559000815344. Its totient is φ = 742381340480.

The previous prime is 1141411311109. The next prime is 1141411311119. The reversal of 1141411311111 is 1111131141411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1141411311111 - 21 = 1141411311109 is a prime.

It is a super-2 number, since 2×11414113111112 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1141411311119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4639883256 + ... + 4639883501.

It is an arithmetic number, because the mean of its divisors is an integer number (194875101918).

Almost surely, 21141411311111 is an apocalyptic number.

1141411311111 is a deficient number, since it is larger than the sum of its proper divisors (417589504233).

1141411311111 is an equidigital number, since it uses as much as digits as its factorization.

1141411311111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9279766801.

The product of its digits is 48, while the sum is 21.

Adding to 1141411311111 its reverse (1111131141411), we get a palindrome (2252542452522).

The spelling of 1141411311111 in words is "one trillion, one hundred forty-one billion, four hundred eleven million, three hundred eleven thousand, one hundred eleven".

Divisors: 1 3 41 123 9279766757 27839300271 380470437037 1141411311111