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114141301223 = 153113745471
BaseRepresentation
bin110101001001101011…
…0100000100111100111
3101220121200222212122212
41222103112200213213
53332230133114343
6124234044114035
711150346023645
oct1522326404747
9356550885585
10114141301223
1144452875004
121a15583591b
13a9c0492cc1
14574b1da195
152e8097ec18
hex1a935a09e7

114141301223 has 4 divisors (see below), whose sum is σ = 114142199808. Its totient is φ = 114140402640.

The previous prime is 114141301201. The next prime is 114141301277. The reversal of 114141301223 is 322103141411.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 114141301223 - 216 = 114141235687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114141301523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219623 + ... + 525848.

It is an arithmetic number, because the mean of its divisors is an integer number (28535549952).

Almost surely, 2114141301223 is an apocalyptic number.

114141301223 is a deficient number, since it is larger than the sum of its proper divisors (898585).

114141301223 is an equidigital number, since it uses as much as digits as its factorization.

114141301223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 898584.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 114141301223 its reverse (322103141411), we get a palindrome (436244442634).

The spelling of 114141301223 in words is "one hundred fourteen billion, one hundred forty-one million, three hundred one thousand, two hundred twenty-three".

Divisors: 1 153113 745471 114141301223