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114143232055 = 523995517349
BaseRepresentation
bin110101001001101110…
…1111000000000110111
3101220121211121222021011
41222103131320000313
53332231131411210
6124234153333051
711150401315126
oct1522335700067
9356554558234
10114143232055
1144453973736
121a156407187
13a9c09baac8
14574b57dabd
152e80c11d8a
hex1a93778037

114143232055 has 8 divisors (see below), whose sum is σ = 137544984000. Its totient is φ = 90932515296.

The previous prime is 114143232019. The next prime is 114143232059. The reversal of 114143232055 is 550232341411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 114143232055 - 27 = 114143231927 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114143232059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47757480 + ... + 47759869.

It is an arithmetic number, because the mean of its divisors is an integer number (17193123000).

Almost surely, 2114143232055 is an apocalyptic number.

114143232055 is a deficient number, since it is larger than the sum of its proper divisors (23401751945).

114143232055 is an equidigital number, since it uses as much as digits as its factorization.

114143232055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95517593.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 114143232055 its reverse (550232341411), we get a palindrome (664375573466).

The spelling of 114143232055 in words is "one hundred fourteen billion, one hundred forty-three million, two hundred thirty-two thousand, fifty-five".

Divisors: 1 5 239 1195 95517349 477586745 22828646411 114143232055