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11415041442055 = 519120158330969
BaseRepresentation
bin1010011000011100010101…
…1111011000000100000111
31111102021012212100110210201
42212013011133120010013
52444011001102121210
640135555254031331
72255465240216146
oct246070537300407
944367185313721
1011415041442055
113701101339359
12134438a348547
1364a58405b464
142b66c326975d
1514bde885153a
hexa61c57d8107

11415041442055 has 8 divisors (see below), whose sum is σ = 14418999716400. Its totient is φ = 8651399829696.

The previous prime is 11415041442047. The next prime is 11415041442137. The reversal of 11415041442055 is 55024414051411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11415041442055 - 23 = 11415041442047 is a prime.

It is a super-2 number, since 2×114150414420552 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60079165390 + ... + 60079165579.

It is an arithmetic number, because the mean of its divisors is an integer number (1802374964550).

Almost surely, 211415041442055 is an apocalyptic number.

11415041442055 is a deficient number, since it is larger than the sum of its proper divisors (3003958274345).

11415041442055 is a wasteful number, since it uses less digits than its factorization.

11415041442055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120158330993.

The product of its (nonzero) digits is 64000, while the sum is 37.

Adding to 11415041442055 its reverse (55024414051411), we get a palindrome (66439455493466).

The spelling of 11415041442055 in words is "eleven trillion, four hundred fifteen billion, forty-one million, four hundred forty-two thousand, fifty-five".

Divisors: 1 5 19 95 120158330969 600791654845 2283008288411 11415041442055