Base | Representation |
---|---|
bin | 110101001010000000… |
… | …1100111110000001001 |
3 | 101220122111021001021121 |
4 | 1222110001213300021 |
5 | 3332241031241013 |
6 | 124235130235241 |
7 | 11150544053446 |
oct | 1522401476011 |
9 | 356574231247 |
10 | 114152602633 |
11 | 44459193a13 |
12 | 1a159585b21 |
13 | a9c291c024 |
14 | 574c8dc9cd |
15 | 2e8196358d |
hex | 1a94067c09 |
114152602633 has 4 divisors (see below), whose sum is σ = 114155946000. Its totient is φ = 114149259268.
The previous prime is 114152602591. The next prime is 114152602639. The reversal of 114152602633 is 336206251411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 336206251411 = 471439 ⋅713149.
It is a cyclic number.
It is not a de Polignac number, because 114152602633 - 29 = 114152602121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114152602639) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1619935 + ... + 1688932.
It is an arithmetic number, because the mean of its divisors is an integer number (28538986500).
Almost surely, 2114152602633 is an apocalyptic number.
It is an amenable number.
114152602633 is a deficient number, since it is larger than the sum of its proper divisors (3343367).
114152602633 is an equidigital number, since it uses as much as digits as its factorization.
114152602633 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3343366.
The product of its (nonzero) digits is 25920, while the sum is 34.
The spelling of 114152602633 in words is "one hundred fourteen billion, one hundred fifty-two million, six hundred two thousand, six hundred thirty-three".
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