11415313003 has 4 divisors (see below), whose sum is σ = 11415897000. Its totient is φ = 11414729008.

The previous prime is 11415312977. The next prime is 11415313037. The reversal of 11415313003 is 30031351411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30031351411 = 17 ⋅1766550083.

It is a cyclic number.

It is not a de Polignac number, because 11415313003 - 2²¹ = 11413215851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11415313073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261625 + ... + 302122.

It is an arithmetic number, because the mean of its divisors is an integer number (2853974250).

Almost surely, 2^11415313003 is an apocalyptic number.

11415313003 is a deficient number, since it is larger than the sum of its proper divisors (583997).

11415313003 is an equidigital number, since it uses as much as digits as its factorization.

11415313003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 583996.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11415313003 its reverse (30031351411), we get a palindrome (41446664414).

The spelling of 11415313003 in words is "eleven billion, four hundred fifteen million, three hundred thirteen thousand, three".