Base | Representation |
---|---|
bin | 10101010000100011… |
… | …11101101001101011 |
3 | 1002110101222102211012 |
4 | 22220101331221223 |
5 | 141333240401401 |
6 | 5124304454135 |
7 | 552554506532 |
oct | 125021755153 |
9 | 32411872735 |
10 | 11413215851 |
11 | 492750aaa4 |
12 | 226631a34b |
13 | 10cb71547b |
14 | 7a3b15319 |
15 | 46beb38bb |
hex | 2a847da6b |
11413215851 has 2 divisors, whose sum is σ = 11413215852. Its totient is φ = 11413215850.
The previous prime is 11413215833. The next prime is 11413215857. The reversal of 11413215851 is 15851231411.
It is a strong prime.
It is an emirp because it is prime and its reverse (15851231411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413215851 is a prime.
It is a super-2 number, since 2×114132158512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11413215857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706607925 + 5706607926.
It is an arithmetic number, because the mean of its divisors is an integer number (5706607926).
Almost surely, 211413215851 is an apocalyptic number.
11413215851 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413215851 is an equidigital number, since it uses as much as digits as its factorization.
11413215851 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4800, while the sum is 32.
The spelling of 11413215851 in words is "eleven billion, four hundred thirteen million, two hundred fifteen thousand, eight hundred fifty-one".
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