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11420023 = 15772739
BaseRepresentation
bin101011100100…
…000101110111
3210111012022211
4223210011313
510410420043
61044434251
7166032346
oct53440567
923435284
1011420023
1164a003a
1239a8987
13249b014
141733b5d
151008a9d
hexae4177

11420023 has 4 divisors (see below), whose sum is σ = 11492920. Its totient is φ = 11347128.

The previous prime is 11420009. The next prime is 11420027. The reversal of 11420023 is 32002411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11420023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11419985 and 11420012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11420027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36213 + ... + 36526.

It is an arithmetic number, because the mean of its divisors is an integer number (2873230).

Almost surely, 211420023 is an apocalyptic number.

11420023 is a deficient number, since it is larger than the sum of its proper divisors (72897).

11420023 is an equidigital number, since it uses as much as digits as its factorization.

11420023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72896.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 11420023 is about 3379.3524527637. The cubic root of 11420023 is about 225.1934007912.

Adding to 11420023 its reverse (32002411), we get a palindrome (43422434).

The spelling of 11420023 in words is "eleven million, four hundred twenty thousand, twenty-three".

Divisors: 1 157 72739 11420023