Base | Representation |
---|---|
bin | 11001111101110111000000… |
… | …011000111111100000100011 |
3 | 112222100121121121220101020121 |
4 | 121331313000120333200203 |
5 | 104432041411440213103 |
6 | 1042515420533221111 |
7 | 33024554553464161 |
oct | 3175670030774043 |
9 | 488317547811217 |
10 | 114202113210403 |
11 | 3342a931734239 |
12 | 10985174791797 |
13 | 4b952a0150aca |
14 | 202b5a9c8a231 |
15 | d309d44186bd |
hex | 67ddc063f823 |
114202113210403 has 8 divisors (see below), whose sum is σ = 118217687821200. Its totient is φ = 110191709980128.
The previous prime is 114202113210257. The next prime is 114202113210421. The reversal of 114202113210403 is 304012311202411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114202113210403 - 241 = 112003089954851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114202113210473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1292800188 + ... + 1292888521.
It is an arithmetic number, because the mean of its divisors is an integer number (14777210977650).
Almost surely, 2114202113210403 is an apocalyptic number.
114202113210403 is a deficient number, since it is larger than the sum of its proper divisors (4015574610797).
114202113210403 is a wasteful number, since it uses less digits than its factorization.
114202113210403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2585690261.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 114202113210403 its reverse (304012311202411), we get a palindrome (418214424412814).
The spelling of 114202113210403 in words is "one hundred fourteen trillion, two hundred two billion, one hundred thirteen million, two hundred ten thousand, four hundred three".
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