Base | Representation |
---|---|
bin | 11001111101111111100000… |
… | …100110000010010101000011 |
3 | 112222101111011221000212021102 |
4 | 121331333200212002111003 |
5 | 104432214111304412311 |
6 | 1042523530525445015 |
7 | 33025330040223560 |
oct | 3175774046022503 |
9 | 488344157025242 |
10 | 114211243435331 |
11 | 33433797490379 |
12 | 10986aa241076b |
13 | 4b960c6898073 |
14 | 202bbd46bd867 |
15 | d30d6ac6a43b |
hex | 67dfe0982543 |
114211243435331 has 16 divisors (see below), whose sum is σ = 130906145399040. Its totient is φ = 97611106276320.
The previous prime is 114211243435297. The next prime is 114211243435339. The reversal of 114211243435331 is 133534342112411.
It is not a de Polignac number, because 114211243435331 - 218 = 114211243173187 is a prime.
It is a super-2 number, since 2×1142112434353312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114211243435339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116538821 + ... + 117514761.
It is an arithmetic number, because the mean of its divisors is an integer number (8181634087440).
Almost surely, 2114211243435331 is an apocalyptic number.
114211243435331 is a deficient number, since it is larger than the sum of its proper divisors (16694901963709).
114211243435331 is an equidigital number, since it uses as much as digits as its factorization.
114211243435331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1024474.
The product of its digits is 103680, while the sum is 38.
Adding to 114211243435331 its reverse (133534342112411), we get a palindrome (247745585547742).
The spelling of 114211243435331 in words is "one hundred fourteen trillion, two hundred eleven billion, two hundred forty-three million, four hundred thirty-five thousand, three hundred thirty-one".
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