Base | Representation |
---|---|
bin | 1010011000110011000010… |
… | …0100110111100111001011 |
3 | 1111102211221101201021000021 |
4 | 2212030300210313213023 |
5 | 2444110440022331103 |
6 | 40142443541321311 |
7 | 2256102215544433 |
oct | 246146044674713 |
9 | 44384841637007 |
10 | 11421133011403 |
11 | 3703747922595 |
12 | 13455aa406237 |
13 | 64b0150a856b |
14 | 2b6b002b32c3 |
15 | 14c153525bbd |
hex | a63309379cb |
11421133011403 has 8 divisors (see below), whose sum is σ = 12015218833200. Its totient is φ = 10840397432928.
The previous prime is 11421133011401. The next prime is 11421133011427. The reversal of 11421133011403 is 30411033112411.
11421133011403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11421133011403 - 21 = 11421133011401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11421133011401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3337559076 + ... + 3337562497.
It is an arithmetic number, because the mean of its divisors is an integer number (1501902354150).
Almost surely, 211421133011403 is an apocalyptic number.
11421133011403 is a deficient number, since it is larger than the sum of its proper divisors (594085821797).
11421133011403 is an equidigital number, since it uses as much as digits as its factorization.
11421133011403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6675121661.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 11421133011403 its reverse (30411033112411), we get a palindrome (41832166123814).
The spelling of 11421133011403 in words is "eleven trillion, four hundred twenty-one billion, one hundred thirty-three million, eleven thousand, four hundred three".
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