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114221404203 = 338073801401
BaseRepresentation
bin110101001100000100…
…0000101000000101011
3101220211021201112021220
41222120020011000223
53332411134413303
6124250025033123
711152340626224
oct1523010050053
9356737645256
10114221404203
1144494006615
121a1786257a3
13aa03c5b20a
145757acc24b
152e87a04053
hex1a9820502b

114221404203 has 4 divisors (see below), whose sum is σ = 152295205608. Its totient is φ = 76147602800.

The previous prime is 114221404189. The next prime is 114221404249. The reversal of 114221404203 is 302404122411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114221404203 - 221 = 114219307051 is a prime.

It is not an unprimeable number, because it can be changed into a prime (114221404903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19036900698 + ... + 19036900703.

It is an arithmetic number, because the mean of its divisors is an integer number (38073801402).

Almost surely, 2114221404203 is an apocalyptic number.

114221404203 is a deficient number, since it is larger than the sum of its proper divisors (38073801405).

114221404203 is an equidigital number, since it uses as much as digits as its factorization.

114221404203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38073801404.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 114221404203 its reverse (302404122411), we get a palindrome (416625526614).

The spelling of 114221404203 in words is "one hundred fourteen billion, two hundred twenty-one million, four hundred four thousand, two hundred three".

Divisors: 1 3 38073801401 114221404203