Base | Representation |
---|---|
bin | 11001111110001010100000… |
… | …011001100111111000100111 |
3 | 112222102121122211200122020000 |
4 | 121332022200121213320213 |
5 | 104432412302120410401 |
6 | 1042533202334112343 |
7 | 33026225456611551 |
oct | 3176124031477047 |
9 | 488377584618200 |
10 | 114223051341351 |
11 | 334387a6769997 |
12 | 1098923894b6b3 |
13 | 4b97258cb2cc4 |
14 | 202c5d49b64d1 |
15 | d3130c6e4186 |
hex | 67e2a0667e27 |
114223051341351 has 20 divisors (see below), whose sum is σ = 178048170209712. Its totient is φ = 72837887810688.
The previous prime is 114223051341317. The next prime is 114223051341403. The reversal of 114223051341351 is 153143150322411.
114223051341351 is a `hidden beast` number, since 1 + 1 + 4 + 2 + 2 + 3 + 0 + 513 + 4 + 135 + 1 = 666.
It is not a de Polignac number, because 114223051341351 - 223 = 114223042952743 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114223051346351) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 30655674826 + ... + 30655678551.
Almost surely, 2114223051341351 is an apocalyptic number.
114223051341351 is a deficient number, since it is larger than the sum of its proper divisors (63825118868361).
114223051341351 is an equidigital number, since it uses as much as digits as its factorization.
114223051341351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61311353412 (or 61311353403 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 36.
The spelling of 114223051341351 in words is "one hundred fourteen trillion, two hundred twenty-three billion, fifty-one million, three hundred forty-one thousand, three hundred fifty-one".
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