114225154403133 has 4 divisors (see below), whose sum is σ = 152300205870848. Its totient is φ = 76150102935420.

The previous prime is 114225154403093. The next prime is 114225154403179. The reversal of 114225154403133 is 331304451522411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-114225154403133 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114225154403091 and 114225154403100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114225154405133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19037525733853 + ... + 19037525733858.

It is an arithmetic number, because the mean of its divisors is an integer number (38075051467712).

Almost surely, 2^{114225154403133} is an apocalyptic number.

It is an amenable number.

114225154403133 is a deficient number, since it is larger than the sum of its proper divisors (38075051467715).

114225154403133 is an equidigital number, since it uses as much as digits as its factorization.

114225154403133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38075051467714.

The product of its (nonzero) digits is 172800, while the sum is 39.

The spelling of 114225154403133 in words is "one hundred fourteen trillion, two hundred twenty-five billion, one hundred fifty-four million, four hundred three thousand, one hundred thirty-three".