Base | Representation |
---|---|
bin | 11001111110001100100010… |
… | …010010000101001000000111 |
3 | 112222102211021200222101120000 |
4 | 121332030202102011020013 |
5 | 104432431232440331210 |
6 | 1042534202455012343 |
7 | 33026333456410323 |
oct | 3176144222051007 |
9 | 488384250871500 |
10 | 114225230402055 |
11 | 33439714797503 |
12 | 1098974666a0b3 |
13 | 4b97515592836 |
14 | 202c760162983 |
15 | d313d8b76ac0 |
hex | 67e322485207 |
114225230402055 has 40 divisors (see below), whose sum is σ = 205498505363712. Its totient is φ = 60700194580032.
The previous prime is 114225230402039. The next prime is 114225230402081. The reversal of 114225230402055 is 550204032522411.
114225230402055 is a `hidden beast` number, since 1 + 1 + 4 + 22 + 523 + 0 + 40 + 20 + 55 = 666.
It is not a de Polignac number, because 114225230402055 - 24 = 114225230402039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 508980967 + ... + 509205336.
Almost surely, 2114225230402055 is an apocalyptic number.
114225230402055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114225230402055 is a deficient number, since it is larger than the sum of its proper divisors (91273274961657).
114225230402055 is a wasteful number, since it uses less digits than its factorization.
114225230402055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1018186597 (or 1018186588 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 36.
Adding to 114225230402055 its reverse (550204032522411), we get a palindrome (664429262924466).
The spelling of 114225230402055 in words is "one hundred fourteen trillion, two hundred twenty-five billion, two hundred thirty million, four hundred two thousand, fifty-five".
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