Base | Representation |
---|---|
bin | 11001111110010001000000… |
… | …101011111000100010111101 |
3 | 112222110021200120112010020101 |
4 | 121332101000223320202331 |
5 | 104433021103033400140 |
6 | 1042540315343521101 |
7 | 33026563523553514 |
oct | 3176210053704275 |
9 | 488407616463211 |
10 | 114230035450045 |
11 | 3344076004a149 |
12 | 1098a6678b9191 |
13 | 4b97accc139b8 |
14 | 202ca9839767b |
15 | d315ba91e99a |
hex | 67e440af88bd |
114230035450045 has 16 divisors (see below), whose sum is σ = 139354239919680. Its totient is φ = 89872445303424.
The previous prime is 114230035450009. The next prime is 114230035450057. The reversal of 114230035450045 is 540054530032411.
It is a cyclic number.
It is not a de Polignac number, because 114230035450045 - 219 = 114230034925757 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114230035449986 and 114230035450013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 450822915 + ... + 451076224.
It is an arithmetic number, because the mean of its divisors is an integer number (8709639994980).
Almost surely, 2114230035450045 is an apocalyptic number.
It is an amenable number.
114230035450045 is a deficient number, since it is larger than the sum of its proper divisors (25124204469635).
114230035450045 is an equidigital number, since it uses as much as digits as its factorization.
114230035450045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 901899564.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 114230035450045 its reverse (540054530032411), we get a palindrome (654284565482456).
The spelling of 114230035450045 in words is "one hundred fourteen trillion, two hundred thirty billion, thirty-five million, four hundred fifty thousand, forty-five".
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