114231130544441 has 4 divisors (see below), whose sum is σ = 114231152202612. Its totient is φ = 114231108886272.

The previous prime is 114231130544429. The next prime is 114231130544483. The reversal of 114231130544441 is 144445031132411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 70634426816041 + 43596703728400 = 8404429^2 + 6602780^2 .

It is a cyclic number.

It is not a de Polignac number, because 114231130544441 - 2³⁸ = 113956252637497 is a prime.

It is a super-2 number, since 2×114231130544441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114231130544395 and 114231130544404.

It is not an unprimeable number, because it can be changed into a prime (114231130544411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2800085 + ... + 15372141.

It is an arithmetic number, because the mean of its divisors is an integer number (28557788050653).

Almost surely, 2^{114231130544441} is an apocalyptic number.

It is an amenable number.

114231130544441 is a deficient number, since it is larger than the sum of its proper divisors (21658171).

114231130544441 is an equidigital number, since it uses as much as digits as its factorization.

114231130544441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21658170.

The product of its (nonzero) digits is 92160, while the sum is 38.

Adding to 114231130544441 its reverse (144445031132411), we get a palindrome (258676161676852).

The spelling of 114231130544441 in words is "one hundred fourteen trillion, two hundred thirty-one billion, one hundred thirty million, five hundred forty-four thousand, four hundred forty-one".