11423213433 has 16 divisors (see below), whose sum is σ = 17210116800. Its totient is φ = 7486398720.

The previous prime is 11423213429. The next prime is 11423213447. The reversal of 11423213433 is 33431232411.

It is a happy number.

11423213433 is a `hidden beast` number, since 1 + 14 + 2 + 3 + 213 + 433 = 666.

11423213433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11423213433 - 2² = 11423213429 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 11423213397 and 11423213406.

It is not an unprimeable number, because it can be changed into a prime (11423213413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3583848 + ... + 3587033.

It is an arithmetic number, because the mean of its divisors is an integer number (1075632300).

Almost surely, 2^11423213433 is an apocalyptic number.

It is an amenable number.

11423213433 is a deficient number, since it is larger than the sum of its proper divisors (5786903367).

11423213433 is an equidigital number, since it uses as much as digits as its factorization.

11423213433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7170949 (or 7170943 counting only the distinct ones).

The product of its digits is 5184, while the sum is 27.

Adding to 11423213433 its reverse (33431232411), we get a palindrome (44854445844).

The spelling of 11423213433 in words is "eleven billion, four hundred twenty-three million, two hundred thirteen thousand, four hundred thirty-three".