1142323454031 has 4 divisors (see below), whose sum is σ = 1523097938712. Its totient is φ = 761548969352.

The previous prime is 1142323454011. The next prime is 1142323454053. The reversal of 1142323454031 is 1304543232411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1142323454031 - 2⁷ = 1142323453903 is a prime.

It is a super-3 number, since 3×1142323454031³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1142323453983 and 1142323454001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1142323454011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190387242336 + ... + 190387242341.

It is an arithmetic number, because the mean of its divisors is an integer number (380774484678).

Almost surely, 2^{1142323454031} is an apocalyptic number.

1142323454031 is a deficient number, since it is larger than the sum of its proper divisors (380774484681).

1142323454031 is an equidigital number, since it uses as much as digits as its factorization.

1142323454031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 380774484680.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 1142323454031 its reverse (1304543232411), we get a palindrome (2446866686442).

The spelling of 1142323454031 in words is "one trillion, one hundred forty-two billion, three hundred twenty-three million, four hundred fifty-four thousand, thirty-one".