Base | Representation |
---|---|
bin | 11001111110010011001111… |
… | …000011100111010000011001 |
3 | 112222110111212001001211021220 |
4 | 121332103033003213100121 |
5 | 104433041001023112403 |
6 | 1042541352351322253 |
7 | 33030006646316211 |
oct | 3176231703472031 |
9 | 488414761054256 |
10 | 114232424035353 |
11 | 33441776375698 |
12 | 1098b013820389 |
13 | 4b980c0a33ba0 |
14 | 202cc436c5241 |
15 | d316aa48d953 |
hex | 67e4cf0e7419 |
114232424035353 has 32 divisors (see below), whose sum is σ = 164395471968000. Its totient is φ = 70138558242816.
The previous prime is 114232424035337. The next prime is 114232424035361. The reversal of 114232424035353 is 353530424232411.
It is not a de Polignac number, because 114232424035353 - 24 = 114232424035337 is a prime.
It is not an unprimeable number, because it can be changed into a prime (114232424035363) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1224480076 + ... + 1224573362.
It is an arithmetic number, because the mean of its divisors is an integer number (5137358499000).
Almost surely, 2114232424035353 is an apocalyptic number.
114232424035353 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
114232424035353 is a deficient number, since it is larger than the sum of its proper divisors (50163047932647).
114232424035353 is a wasteful number, since it uses less digits than its factorization.
114232424035353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163681.
The product of its (nonzero) digits is 1036800, while the sum is 42.
Adding to 114232424035353 its reverse (353530424232411), we get a palindrome (467762848267764).
The spelling of 114232424035353 in words is "one hundred fourteen trillion, two hundred thirty-two billion, four hundred twenty-four million, thirty-five thousand, three hundred fifty-three".
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