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11423340241 = 23496666967
BaseRepresentation
bin10101010001110001…
…00101011011010001
31002111010000210212121
422220320211123101
5141343333341431
65125305454241
7553036534645
oct125070453321
932433023777
1011423340241
1149321a5665
1222697a1381
13110084b831
147a51ccc25
1546cd13611
hex2a8e256d1

11423340241 has 4 divisors (see below), whose sum is σ = 11920007232. Its totient is φ = 10926673252.

The previous prime is 11423340211. The next prime is 11423340293. The reversal of 11423340241 is 14204332411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14204332411 = 35407401173.

It is a cyclic number.

It is not a de Polignac number, because 11423340241 - 29 = 11423339729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11423340211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248333461 + ... + 248333506.

It is an arithmetic number, because the mean of its divisors is an integer number (2980001808).

Almost surely, 211423340241 is an apocalyptic number.

It is an amenable number.

11423340241 is a deficient number, since it is larger than the sum of its proper divisors (496666991).

11423340241 is an equidigital number, since it uses as much as digits as its factorization.

11423340241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 496666990.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 11423340241 its reverse (14204332411), we get a palindrome (25627672652).

The spelling of 11423340241 in words is "eleven billion, four hundred twenty-three million, three hundred forty thousand, two hundred forty-one".

Divisors: 1 23 496666967 11423340241