Base | Representation |
---|---|
bin | 11001111110011010011111… |
… | …011001010100000010101010 |
3 | 112222111020221221220220202122 |
4 | 121332122133121110002222 |
5 | 104433202424333231132 |
6 | 1042545121401031242 |
7 | 33030404003031602 |
oct | 3176323731240252 |
9 | 488436857826678 |
10 | 114240214352042 |
11 | 33445003846949 |
12 | 10990628785522 |
13 | 4b98a629ac32c |
14 | 202d3821a9c02 |
15 | d319b436a912 |
hex | 67e69f6540aa |
114240214352042 has 8 divisors (see below), whose sum is σ = 175991681569476. Its totient is φ = 55576320495552.
The previous prime is 114240214352021. The next prime is 114240214352101. The reversal of 114240214352042 is 240253412042411.
It can be written as a sum of positive squares in 2 ways, for example, as 110084980795321 + 4155233556721 = 10492139^2 + 2038439^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 114240214351993 and 114240214352011.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 771893340143 + ... + 771893340290.
Almost surely, 2114240214352042 is an apocalyptic number.
114240214352042 is a deficient number, since it is larger than the sum of its proper divisors (61751467217434).
114240214352042 is a wasteful number, since it uses less digits than its factorization.
114240214352042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1543786680472.
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 114240214352042 its reverse (240253412042411), we get a palindrome (354493626394453).
The spelling of 114240214352042 in words is "one hundred fourteen trillion, two hundred forty billion, two hundred fourteen million, three hundred fifty-two thousand, forty-two".
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