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114240214352042 = 2371543786680433
BaseRepresentation
bin11001111110011010011111…
…011001010100000010101010
3112222111020221221220220202122
4121332122133121110002222
5104433202424333231132
61042545121401031242
733030404003031602
oct3176323731240252
9488436857826678
10114240214352042
1133445003846949
1210990628785522
134b98a629ac32c
14202d3821a9c02
15d319b436a912
hex67e69f6540aa

114240214352042 has 8 divisors (see below), whose sum is σ = 175991681569476. Its totient is φ = 55576320495552.

The previous prime is 114240214352021. The next prime is 114240214352101. The reversal of 114240214352042 is 240253412042411.

It can be written as a sum of positive squares in 2 ways, for example, as 110084980795321 + 4155233556721 = 10492139^2 + 2038439^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 114240214351993 and 114240214352011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 771893340143 + ... + 771893340290.

Almost surely, 2114240214352042 is an apocalyptic number.

114240214352042 is a deficient number, since it is larger than the sum of its proper divisors (61751467217434).

114240214352042 is a wasteful number, since it uses less digits than its factorization.

114240214352042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1543786680472.

The product of its (nonzero) digits is 61440, while the sum is 35.

Adding to 114240214352042 its reverse (240253412042411), we get a palindrome (354493626394453).

The spelling of 114240214352042 in words is "one hundred fourteen trillion, two hundred forty billion, two hundred fourteen million, three hundred fifty-two thousand, forty-two".

Divisors: 1 2 37 74 1543786680433 3087573360866 57120107176021 114240214352042