Base | Representation |
---|---|
bin | 11001111110011011011010… |
… | …011100011011101001111011 |
3 | 112222111100112000001100010121 |
4 | 121332123122130123221323 |
5 | 104433211441441303103 |
6 | 1042545403550354111 |
7 | 33030440362436251 |
oct | 3176333234335173 |
9 | 488440460040117 |
10 | 114241205025403 |
11 | 33445471a7a465 |
12 | 109908644bb937 |
13 | 4b98b900022a1 |
14 | 202d4379aa5d1 |
15 | d31a213086bd |
hex | 67e6da71ba7b |
114241205025403 has 16 divisors (see below), whose sum is σ = 120521179440000. Its totient is φ = 107987974846272.
The previous prime is 114241205025349. The next prime is 114241205025419. The reversal of 114241205025403 is 304520502142411.
It is not a de Polignac number, because 114241205025403 - 217 = 114241204894331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114241205025443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 271211448 + ... + 271632346.
It is an arithmetic number, because the mean of its divisors is an integer number (7532573715000).
Almost surely, 2114241205025403 is an apocalyptic number.
114241205025403 is a deficient number, since it is larger than the sum of its proper divisors (6279974414597).
114241205025403 is a wasteful number, since it uses less digits than its factorization.
114241205025403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 452634.
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 114241205025403 its reverse (304520502142411), we get a palindrome (418761707167814).
The spelling of 114241205025403 in words is "one hundred fourteen trillion, two hundred forty-one billion, two hundred five million, twenty-five thousand, four hundred three".
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