114241511313013 has 4 divisors (see below), whose sum is σ = 130561727214880. Its totient is φ = 97921295411148.

The previous prime is 114241511313011. The next prime is 114241511313031. The reversal of 114241511313013 is 310313115142411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114241511313013 - 2¹ = 114241511313011 is a prime.

It is a super-2 number, since 2×114241511313013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114241511313011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8160107950923 + ... + 8160107950936.

It is an arithmetic number, because the mean of its divisors is an integer number (32640431803720).

Almost surely, 2^{114241511313013} is an apocalyptic number.

It is an amenable number.

114241511313013 is a deficient number, since it is larger than the sum of its proper divisors (16320215901867).

114241511313013 is an equidigital number, since it uses as much as digits as its factorization.

114241511313013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16320215901866.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 114241511313013 its reverse (310313115142411), we get a palindrome (424554626455424).

The spelling of 114241511313013 in words is "one hundred fourteen trillion, two hundred forty-one billion, five hundred eleven million, three hundred thirteen thousand, thirteen".