114242131410133 has 4 divisors (see below), whose sum is σ = 114250715248780. Its totient is φ = 114233547571488.

The previous prime is 114242131410109. The next prime is 114242131410247. The reversal of 114242131410133 is 331014131242411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10024208206609 + 104217923203524 = 3166103^2 + 10208718^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114242131410133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114242131410095 and 114242131410104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114242131414133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4291899360 + ... + 4291925977.

It is an arithmetic number, because the mean of its divisors is an integer number (28562678812195).

Almost surely, 2^{114242131410133} is an apocalyptic number.

It is an amenable number.

114242131410133 is a deficient number, since it is larger than the sum of its proper divisors (8583838647).

114242131410133 is an equidigital number, since it uses as much as digits as its factorization.

114242131410133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8583838646.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 114242131410133 its reverse (331014131242411), we get a palindrome (445256262652544).

The spelling of 114242131410133 in words is "one hundred fourteen trillion, two hundred forty-two billion, one hundred thirty-one million, four hundred ten thousand, one hundred thirty-three".