Base | Representation |
---|---|
bin | 11001111110011100010001… |
… | …101010101111011100010001 |
3 | 112222111102220120102022101012 |
4 | 121332130101222233130101 |
5 | 104433220341132221340 |
6 | 1042550035524420305 |
7 | 33030502342516400 |
oct | 3176342152573421 |
9 | 488442816368335 |
10 | 114242131523345 |
11 | 334458a7a60041 |
12 | 10990a82847695 |
13 | 4b98ca9c45917 |
14 | 202d4c4a63637 |
15 | d31a7781b565 |
hex | 67e711aaf711 |
114242131523345 has 24 divisors (see below), whose sum is σ = 162175616683200. Its totient is φ = 77009708019552.
The previous prime is 114242131523297. The next prime is 114242131523383. The reversal of 114242131523345 is 543325131242411.
It is not a de Polignac number, because 114242131523345 - 214 = 114242131506961 is a prime.
It is a super-2 number, since 2×1142421315233452 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3951633125 + ... + 3951662034.
It is an arithmetic number, because the mean of its divisors is an integer number (6757317361800).
Almost surely, 2114242131523345 is an apocalyptic number.
It is an amenable number.
114242131523345 is a deficient number, since it is larger than the sum of its proper divisors (47933485159855).
114242131523345 is an equidigital number, since it uses as much as digits as its factorization.
114242131523345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7903295237 (or 7903295230 counting only the distinct ones).
The product of its digits is 345600, while the sum is 41.
Adding to 114242131523345 its reverse (543325131242411), we get a palindrome (657567262765756).
The spelling of 114242131523345 in words is "one hundred fourteen trillion, two hundred forty-two billion, one hundred thirty-one million, five hundred twenty-three thousand, three hundred forty-five".
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