Search a number
-
+
114244143001 = 227503278163
BaseRepresentation
bin110101001100101111…
…0110100011110011001
3101220212212111210001121
41222121132310132121
53332433000034001
6124252200245241
711153035123132
oct1523136643631
9356785453047
10114244143001
11444a592760a
121a184170821
13aa08890121
14575ab2ac89
152e899e66a1
hex1a997b4799

114244143001 has 4 divisors (see below), whose sum is σ = 114747421392. Its totient is φ = 113740864612.

The previous prime is 114244142981. The next prime is 114244143007. The reversal of 114244143001 is 100341442411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114244143001 - 221 = 114242045849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114244143007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251638855 + ... + 251639308.

It is an arithmetic number, because the mean of its divisors is an integer number (28686855348).

Almost surely, 2114244143001 is an apocalyptic number.

It is an amenable number.

114244143001 is a deficient number, since it is larger than the sum of its proper divisors (503278391).

114244143001 is an equidigital number, since it uses as much as digits as its factorization.

114244143001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 503278390.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 114244143001 its reverse (100341442411), we get a palindrome (214585585412).

The spelling of 114244143001 in words is "one hundred fourteen billion, two hundred forty-four million, one hundred forty-three thousand, one".

Divisors: 1 227 503278163 114244143001