114254031125132 has 6 divisors (see below), whose sum is σ = 199944554468988. Its totient is φ = 57127015562564.

The previous prime is 114254031125093. The next prime is 114254031125147. The reversal of 114254031125132 is 231521130452411.

It is a junction number, because it is equal to n+sod(n) for n = 114254031125092 and 114254031125101.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14281753890638 + ... + 14281753890645.

It is an arithmetic number, because the mean of its divisors is an integer number (33324092411498).

Almost surely, 2^{114254031125132} is an apocalyptic number.

It is an amenable number.

114254031125132 is a deficient number, since it is larger than the sum of its proper divisors (85690523343856).

114254031125132 is a wasteful number, since it uses less digits than its factorization.

114254031125132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28563507781287 (or 28563507781285 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 114254031125132 its reverse (231521130452411), we get a palindrome (345775161577543).

The spelling of 114254031125132 in words is "one hundred fourteen trillion, two hundred fifty-four billion, thirty-one million, one hundred twenty-five thousand, one hundred thirty-two".