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114255031441555 = 522851006288311
BaseRepresentation
bin11001111110101000010010…
…100100000001100010010011
3112222112200012120220001102201
4121332220102210001202103
5104433423301022112210
61043000011542424031
733031440122151364
oct3176502244014223
9488480176801381
10114255031441555
1133450317698574
1210993482a32017
134b9a284675814
14202dd89db9b6b
15d3208009e53a
hex67ea12901893

114255031441555 has 4 divisors (see below), whose sum is σ = 137106037729872. Its totient is φ = 91404025153240.

The previous prime is 114255031441547. The next prime is 114255031441567. The reversal of 114255031441555 is 555144130552411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 114255031441555 - 23 = 114255031441547 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11425503144151 + ... + 11425503144160.

It is an arithmetic number, because the mean of its divisors is an integer number (34276509432468).

Almost surely, 2114255031441555 is an apocalyptic number.

114255031441555 is a deficient number, since it is larger than the sum of its proper divisors (22851006288317).

114255031441555 is an equidigital number, since it uses as much as digits as its factorization.

114255031441555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22851006288316.

The product of its (nonzero) digits is 1200000, while the sum is 46.

Adding to 114255031441555 its reverse (555144130552411), we get a palindrome (669399161993966).

The spelling of 114255031441555 in words is "one hundred fourteen trillion, two hundred fifty-five billion, thirty-one million, four hundred forty-one thousand, five hundred fifty-five".

Divisors: 1 5 22851006288311 114255031441555