Base | Representation |
---|---|
bin | 11001111110101000010010… |
… | …100100000001100010010011 |
3 | 112222112200012120220001102201 |
4 | 121332220102210001202103 |
5 | 104433423301022112210 |
6 | 1043000011542424031 |
7 | 33031440122151364 |
oct | 3176502244014223 |
9 | 488480176801381 |
10 | 114255031441555 |
11 | 33450317698574 |
12 | 10993482a32017 |
13 | 4b9a284675814 |
14 | 202dd89db9b6b |
15 | d3208009e53a |
hex | 67ea12901893 |
114255031441555 has 4 divisors (see below), whose sum is σ = 137106037729872. Its totient is φ = 91404025153240.
The previous prime is 114255031441547. The next prime is 114255031441567. The reversal of 114255031441555 is 555144130552411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 114255031441555 - 23 = 114255031441547 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11425503144151 + ... + 11425503144160.
It is an arithmetic number, because the mean of its divisors is an integer number (34276509432468).
Almost surely, 2114255031441555 is an apocalyptic number.
114255031441555 is a deficient number, since it is larger than the sum of its proper divisors (22851006288317).
114255031441555 is an equidigital number, since it uses as much as digits as its factorization.
114255031441555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22851006288316.
The product of its (nonzero) digits is 1200000, while the sum is 46.
Adding to 114255031441555 its reverse (555144130552411), we get a palindrome (669399161993966).
The spelling of 114255031441555 in words is "one hundred fourteen trillion, two hundred fifty-five billion, thirty-one million, four hundred forty-one thousand, five hundred fifty-five".
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