114300021443341 has 4 divisors (see below), whose sum is σ = 114302282577184. Its totient is φ = 114297760309500.

The previous prime is 114300021443299. The next prime is 114300021443357. The reversal of 114300021443341 is 143344120003411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114300021443341 - 2¹⁵ = 114300021410573 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114300021443141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1130491095 + ... + 1130592196.

It is an arithmetic number, because the mean of its divisors is an integer number (28575570644296).

Almost surely, 2^{114300021443341} is an apocalyptic number.

It is an amenable number.

114300021443341 is a deficient number, since it is larger than the sum of its proper divisors (2261133843).

114300021443341 is an equidigital number, since it uses as much as digits as its factorization.

114300021443341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2261133842.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 114300021443341 its reverse (143344120003411), we get a palindrome (257644141446752).

The spelling of 114300021443341 in words is "one hundred fourteen trillion, three hundred billion, twenty-one million, four hundred forty-three thousand, three hundred forty-one".