Base | Representation |
---|---|
bin | 11001111111010010001110… |
… | …001001000111011011011111 |
3 | 112222200222102022121010022212 |
4 | 121333102032021013123133 |
5 | 104440143002413414201 |
6 | 1043032415313431035 |
7 | 33034622621245505 |
oct | 3177221611073337 |
9 | 488628368533285 |
10 | 114300054435551 |
11 | 33468420a29316 |
12 | 109a0148b6b47b |
13 | 4ba15ab277a7a |
14 | 203221b712675 |
15 | d33317a30abb |
hex | 67f48e2476df |
114300054435551 has 4 divisors (see below), whose sum is σ = 115067168895000. Its totient is φ = 113532939976104.
The previous prime is 114300054435443. The next prime is 114300054435559. The reversal of 114300054435551 is 155534450003411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114300054435551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114300054435499 and 114300054435508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114300054435559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383557229501 + ... + 383557229798.
It is an arithmetic number, because the mean of its divisors is an integer number (28766792223750).
Almost surely, 2114300054435551 is an apocalyptic number.
114300054435551 is a deficient number, since it is larger than the sum of its proper divisors (767114459449).
114300054435551 is an equidigital number, since it uses as much as digits as its factorization.
114300054435551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 767114459448.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 114300054435551 in words is "one hundred fourteen trillion, three hundred billion, fifty-four million, four hundred thirty-five thousand, five hundred fifty-one".
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