Base | Representation |
---|---|
bin | 1010011001010100001101… |
… | …1110101110110111110001 |
3 | 1111110200221010222110121201 |
4 | 2212111003132232313301 |
5 | 2444232210231320213 |
6 | 40150515443251201 |
7 | 2256536022564616 |
oct | 246250336566761 |
9 | 44420833873551 |
10 | 11430040104433 |
11 | 37074a87273a5 |
12 | 1347275379b01 |
13 | 64bb04529702 |
14 | 2b730722250d |
15 | 14c4c549e6dd |
hex | a65437aedf1 |
11430040104433 has 16 divisors (see below), whose sum is σ = 11678050632960. Its totient is φ = 11184530447376.
The previous prime is 11430040104421. The next prime is 11430040104449. The reversal of 11430040104433 is 33440104003411.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11430040104433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11430040104533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5889358 + ... + 7585816.
It is an arithmetic number, because the mean of its divisors is an integer number (729878164560).
Almost surely, 211430040104433 is an apocalyptic number.
It is an amenable number.
11430040104433 is a deficient number, since it is larger than the sum of its proper divisors (248010528527).
11430040104433 is a wasteful number, since it uses less digits than its factorization.
11430040104433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1697196.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11430040104433 its reverse (33440104003411), we get a palindrome (44870144107844).
The spelling of 11430040104433 in words is "eleven trillion, four hundred thirty billion, forty million, one hundred four thousand, four hundred thirty-three".
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