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11430040104433 = 672274431696459
BaseRepresentation
bin1010011001010100001101…
…1110101110110111110001
31111110200221010222110121201
42212111003132232313301
52444232210231320213
640150515443251201
72256536022564616
oct246250336566761
944420833873551
1011430040104433
1137074a87273a5
121347275379b01
1364bb04529702
142b730722250d
1514c4c549e6dd
hexa65437aedf1

11430040104433 has 16 divisors (see below), whose sum is σ = 11678050632960. Its totient is φ = 11184530447376.

The previous prime is 11430040104421. The next prime is 11430040104449. The reversal of 11430040104433 is 33440104003411.

It is a happy number.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11430040104433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11430040104533) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5889358 + ... + 7585816.

It is an arithmetic number, because the mean of its divisors is an integer number (729878164560).

Almost surely, 211430040104433 is an apocalyptic number.

It is an amenable number.

11430040104433 is a deficient number, since it is larger than the sum of its proper divisors (248010528527).

11430040104433 is a wasteful number, since it uses less digits than its factorization.

11430040104433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1697196.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 11430040104433 its reverse (33440104003411), we get a palindrome (44870144107844).

The spelling of 11430040104433 in words is "eleven trillion, four hundred thirty billion, forty million, one hundred four thousand, four hundred thirty-three".

Divisors: 1 67 227 443 15209 29681 100561 1696459 6737587 113662753 385096193 751531337 25801444931 50352599579 170597613499 11430040104433